Added a counterexample

This commit is contained in:
ajeffrey@roblox.com 2022-03-25 13:52:39 -05:00
parent ec7c5e3b84
commit afe4700d59

View file

@ -282,3 +282,30 @@ not-quite-set-theoretic-only-if {S₁} {T₁} {S₂} {T₂} s₂ t₂ S₂s₂
r (function-ok t) (function-ok T₁t) with dec-language T₂ t
r (function-ok t) (function-ok T₁t) | Left ¬T₂t = CONTRADICTION (p Q q (s₂ , t) (Right T₁t) (S₂s₂ , language-comp t ¬T₂t))
r (function-ok t) (function-ok T₁t) | Right T₂t = function-ok T₂t
-- A counterexample when the argument type is empty.
set-theoretic-counterexample-one : ( Q Q Comp((Language none) Comp(Language number)) Q Comp((Language none) Comp(Language string)))
set-theoretic-counterexample-one Q q ((scalar s) , u) Qtu (scalar () , p)
set-theoretic-counterexample-one Q q ((function-err t) , u) Qtu (scalar-function-err () , p)
set-theoretic-counterexample-two : (none number) ≮: (none string)
set-theoretic-counterexample-two = witness
(function-ok (scalar number)) (function-ok (scalar number))
(function-ok (scalar-scalar number string (λ ())))
-- At some point we may deal with overloaded function resolution, which should fix this problem...
-- The reason why this is connected to overloaded functions is that currently we have that the type of
-- f(x) is (tgt T) where f:T. Really we should have the type depend on the type of x, that is use (tgt T U),
-- where U is the type of x. In particular (tgt (S => T) (U & V)) should be the same as (tgt ((S&U) => T) V)
-- and tgt(none => T) should be any. For example
--
-- tgt((number => string) & (string => bool))(number)
-- is tgt(number => string)(number) & tgt(string => bool)(number)
-- is tgt(number => string)(number) & tgt(string => bool)(number&any)
-- is tgt(number => string)(number) & tgt(string&number => bool)(any)
-- is tgt(number => string)(number) & tgt(none => bool)(any)
-- is string & any
-- is string
--
-- there's some discussion of this in the Gentle Introduction paper.