Potential fix for process.spawn yield issue

src/lib/globals/process.rs

@@ -1,8 +1,12 @@
-use std::{env, process::Stdio, sync::Weak};
+use std::{
+    env,
+    process::{Command, Stdio},
+    sync::Weak,
+};
 
 use mlua::prelude::*;
 use os_str_bytes::RawOsString;
-use smol::{channel::Sender, process::Command, LocalExecutor};
+use smol::{channel::Sender, unblock};
 
 use crate::{utils::table::TableBuilder, LuneMessage};
 
@@ -116,30 +120,24 @@ async fn process_spawn(
     lua: &Lua,
     (program, args): (String, Option<Vec<String>>),
 ) -> LuaResult<LuaTable> {
-    let exec = lua
+    // Create and spawn a **blocking** child process to prevent
-        .app_data_ref::<Weak<LocalExecutor>>()
-        .unwrap()
-        .upgrade()
-        .unwrap();
-    // Create and spawn a child process in a new task to prevent
     // issues with yielding across the metamethod/c-call boundary
-    let output = exec
+    let pwd = env::current_dir()?;
-        .spawn(async move {
+    let output = unblock(move || {
         let mut cmd = Command::new(program);
         if let Some(args) = args {
             cmd.args(args);
         }
         let child = cmd
-                .current_dir(env::current_dir().map_err(LuaError::external)?)
+            .current_dir(pwd)
             .stdin(Stdio::null())
             .stdout(Stdio::piped())
             .stderr(Stdio::piped())
-                .spawn()
+            .spawn()?;
-                .map_err(LuaError::external)?;
+        child.wait_with_output()
-            let output = child.output().await.map_err(LuaError::external)?;
-            Ok::<_, LuaError>(output)
     })
-        .await?;
+    .await
+    .map_err(LuaError::external)?;
     // NOTE: If an exit code was not given by the child process,
     // we default to 1 if it yielded any error output, otherwise 0
     let code = output