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Fix process.spawn yielding issue
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parent
5839a7b021
commit
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2 changed files with 33 additions and 15 deletions
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@ -5,6 +5,13 @@ All notable changes to this project will be documented in this file.
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The format is based on [Keep a Changelog](https://keepachangelog.com/en/1.0.0/),
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and this project adheres to [Semantic Versioning](https://semver.org/spec/v2.0.0.html).
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## Unreleased
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### Fixed
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- Potential fix for spawned processes that yield erroring
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with "attempt to yield across metamethod/c-call boundary"
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## `0.0.5` - January 22nd, 2023
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### Added
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@ -1,11 +1,12 @@
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use std::{
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env,
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process::{exit, Stdio},
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sync::Weak,
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};
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use mlua::prelude::*;
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use os_str_bytes::RawOsString;
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use smol::process::Command;
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use smol::{process::Command, LocalExecutor};
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use crate::utils::table_builder::TableBuilder;
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@ -116,20 +117,30 @@ async fn process_spawn(
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lua: &Lua,
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(program, args): (String, Option<Vec<String>>),
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) -> LuaResult<LuaTable> {
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// Create and spawn a child process, and
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// wait for it to terminate with output
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let mut cmd = Command::new(program);
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if let Some(args) = args {
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cmd.args(args);
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}
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let child = cmd
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.current_dir(env::current_dir().map_err(LuaError::external)?)
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.stdin(Stdio::null())
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.stdout(Stdio::piped())
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.stderr(Stdio::piped())
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.spawn()
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.map_err(LuaError::external)?;
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let output = child.output().await.map_err(LuaError::external)?;
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let exec = lua
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.app_data_ref::<Weak<LocalExecutor>>()
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.unwrap()
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.upgrade()
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.unwrap();
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// Create and spawn a child process in a new task to prevent
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// issues with yielding across the metamethod/c-call boundary
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let output = exec
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.spawn(async move {
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let mut cmd = Command::new(program);
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if let Some(args) = args {
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cmd.args(args);
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}
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let child = cmd
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.current_dir(env::current_dir().map_err(LuaError::external)?)
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.stdin(Stdio::null())
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.stdout(Stdio::piped())
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.stderr(Stdio::piped())
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.spawn()
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.map_err(LuaError::external)?;
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let output = child.output().await.map_err(LuaError::external)?;
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Ok::<_, LuaError>(output)
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})
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.await?;
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// NOTE: If an exit code was not given by the child process,
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// we default to 1 if it yielded any error output, otherwise 0
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let code = output
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