--[[ MIT License Copyright (c) 2017 Gabriel de Quadros Ligneul Permission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the "Software"), to deal in the Software without restriction, including without limitation the rights to use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is furnished to do so, subject to the following conditions: The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software. THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE. ]] -- The Computer Language Benchmarks Game -- http://benchmarksgame.alioth.debian.org/ -- contributed by Mike Pall local function prequire(name) local success, result = pcall(require, name); return if success then result else nil end local bench = script and require(script.Parent.bench_support) or prequire("bench_support") or require("../../bench_support") function test() local function fannkuch(n) local p, q, s, sign, maxflips, sum = {}, {}, {}, 1, 0, 0 for i=1,n do p[i] = i; q[i] = i; s[i] = i end repeat -- Copy and flip. local q1 = p[1] -- Cache 1st element. if q1 ~= 1 then for i=2,n do q[i] = p[i] end -- Work on a copy. local flips = 1 repeat local qq = q[q1] if qq == 1 then -- ... until 1st element is 1. sum = sum + sign*flips if flips > maxflips then maxflips = flips end -- New maximum? break end q[q1] = q1 if q1 >= 4 then local i, j = 2, q1 - 1 repeat q[i], q[j] = q[j], q[i]; i = i + 1; j = j - 1; until i >= j end q1 = qq; flips = flips + 1 until false end if sign == 1 then p[2], p[1] = p[1], p[2]; sign = -1 -- Rotate 1<-2. else p[2], p[3] = p[3], p[2]; sign = 1 -- Rotate 1<-2 and 1<-2<-3. for i=3,n do local sx = s[i] if sx ~= 1 then s[i] = sx-1; break end if i == n then return sum, maxflips end -- Out of permutations. s[i] = i -- Rotate 1<-...<-i+1. local t = p[1]; for j=1,i do p[j] = p[j+1] end; p[i+1] = t end end until false end local n = tonumber(arg and arg[1]) or 8 local sum, flips = fannkuch(n) print(sum, "\nPfannkuchen(", n, ") = ", flips, "\n") end bench.runCode(test, "fannkuchen-redux")